1-(5/t)-(14/t^2)=0

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Solution for 1-(5/t)-(14/t^2)=0 equation:


D( t )

t^2 = 0

t = 0

t^2 = 0

t^2 = 0

1*t^2 = 0 // : 1

t^2 = 0

t = 0

t = 0

t = 0

t in (-oo:0) U (0:+oo)

1-(5/t)-(14/(t^2)) = 0

1-5*t^-1-14*t^-2 = 0

t_1 = t^-1

1-14*t_1^2-5*t_1^1 = 0

1-14*t_1^2-5*t_1 = 0

DELTA = (-5)^2-(-14*1*4)

DELTA = 81

DELTA > 0

t_1 = (81^(1/2)+5)/(-14*2) or t_1 = (5-81^(1/2))/(-14*2)

t_1 = -1/2 or t_1 = 1/7

t_1 = -1/2

t^-1+1/2 = 0

1*t^-1 = -1/2 // : 1

t^-1 = -1/2

-1 < 0

1/(t^1) = -1/2 // * t^1

1 = -1/2*t^1 // : -1/2

-2 = t^1

t = -2

t_1 = 1/7

t^-1-1/7 = 0

1*t^-1 = 1/7 // : 1

t^-1 = 1/7

-1 < 0

1/(t^1) = 1/7 // * t^1

1 = 1/7*t^1 // : 1/7

7 = t^1

t = 7

t in { -2, 7 }

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